WebExample to Find Maximum Product of Two Elements Example 1: Input: nums = [3,4,5,2] Output: 12 Explanation: If we choose the indices i=1 and j=2 (0 bound array), we will get the maximum value, that is, (nums [1]-1)* (nums [2]-1) = (4-1)* (5-1) = 3*4 = 12. Example 2: Input: nums = [1,5,4,5] Output: 16 Webmax ( array $value_array ): mixed If the first and only parameter is an array, max () returns the highest value in that array. If at least two parameters are provided, max () returns the biggest of these values. Note: Values of different types will be compared using the standard comparison rules.
Find pair with greatest product in array - GeeksforGeeks
WebSep 5, 2016 · Just sort the list and select the largest of the products of the last 2 items in the list and the first 2 items in the list: from operator import mul numbers = [10, 20, 1, -11, 100, -12] l = sorted (numbers) # or sort in place with numbers.sort () if you don't mind mutating the list max_product = max (mul (*l [:2]), mul (*l [-2:])) WebOct 6, 2024 · Suppose we have a list of numbers, we have to find the largest product of two distinct elements. So, if the input is like [5, 3, 7, 4], then the output will be 35 To solve this, we will follow these steps − curr_max := -inf for i in range 0 to size of nums - 1, do for j in range i+1 to size of nums - 1, do if nums [i] * nums [j] > curr_max, then how to save progress on clipchamp
Java program to Find Maximum Product of Two Elements in Array
WebApr 10, 2024 · Iterate through the array and insert all elements in both priority queues. Initialize a variable maximum with the first element in pqmax and remove it from pqmax. Create two variables product1 and product2. product1= maximum*pqmax.poll ()*pqmax.poll (). product2= maximum*pqmin.poll ()*pqmin.poll (). return the greatest of product1 and … WebOct 12, 2024 · Suppose we have a list of numbers called nums, we have to find the largest product of two unique elements. So, if the input is like nums = [8, -3, 1, -5], then the output will be 15, (-3)* (-5) = 15 which is maximum here. To solve this, we will follow these steps − n := size of nums nums_sort := sort the list nums WebSolution - 1: Using two for loop - initialize a max variable - check with every number with other number if multiplication of two number is greater than max Time Complexity: O (n^2)... north face trevail down jacket